leetcode:412. Fizz Buzz(python3解法）

2024-01-08 12:31:25

难度：简单

给你一个整数?n?，找出从?1?到?n?各个整数的 Fizz Buzz 表示，并用字符串数组?answer（下标从 1 开始）返回结果，其中：

  • answer[i] == "FizzBuzz"?如果?i?同时是?3?和?5?的倍数。
  • answer[i] == "Fizz"?如果?i?是?3?的倍数。
  • answer[i] == "Buzz"?如果?i?是?5?的倍数。
  • answer[i] == i?（以字符串形式）如果上述条件全不满足。

示例 1：

输入：n = 3
输出：["1","2","Fizz"]

示例 2：

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例 3：

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

提示：

  • 1 <= n <= 104

题解：

class Solution(object):
    def fizzBuzz(self, n):
        res = []
        for i in range(1,n+1):
            # print(i)
            if i % 3== 0 and i %5 == 0:
                res.append('FizzBuzz')
            elif i%3 == 0:
                res.append('Fizz')
            elif i%5 == 0:
                res.append('Buzz')
            else:
                res.append(str(i))
        return res

文章来源:https://blog.csdn.net/qq_41905051/article/details/135452628
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