【Java基础】--学生管理系统
2023-12-23 06:53:26
题目概述:
需求:采用控制台的形式书写学生管理系统,如下图所示:
代码如下:
public class 学生管理系统_01 {
public static void main(String[] args) {
ArrayList<Student> students = new ArrayList<>();
Scanner scanner = new Scanner(System.in);
while (true) {
System.out.println("--------欢迎来到Boss学生管理系统--------");
System.out.println("1.添加学生");
System.out.println("2.删除学生");
System.out.println("3.修改学生");
System.out.println("4.查询学生");
System.out.println("5.查询所有学生");
System.out.println("6.退出");
System.out.println("请输入你的选择:");
String s = scanner.next();
loop:switch (s) {
case "1":
// System.out.println("请输入学生的id:");
// Integer id = scanner.nextInt();
// boolean mark = true;
// for (int i = 0; i < students.size(); i++) {
// Student student = students.get(i);
// if (student.getId().equals(id)) {
// System.out.println("id重复,请重新输入!");
// mark = false;
// break;
// }
// }
// if (mark) {
// System.out.println("请输入学生的name:");
// String name = scanner.next();
// System.out.println("请输入学生的age:");
// int age = scanner.nextInt();
// System.out.println("请输入学生的address:");
// String address = scanner.next();
// Student stu = new Student(id, name, age, address);
// students.add(stu);
// System.out.println("添加学生成功!");
// }
System.out.println("请输入学生的id:");
Integer id = scanner.nextInt();
for (int i = 0; i < students.size(); i++) {
Student student = students.get(i);
if (student.getId().equals(id)) {
System.out.println("id重复,请重新输入!");
break loop;
}
}
System.out.println("请输入学生的name:");
String name = scanner.next();
System.out.println("请输入学生的age:");
int age = scanner.nextInt();
System.out.println("请输入学生的address:");
String address = scanner.next();
Student stu = new Student(id, name, age, address);
students.add(stu);
System.out.println("添加学生成功!");
break;
case "2":
System.out.println("请输入你要删除学生的id:");
Integer sid = scanner.nextInt();
boolean flag = delectStu(students, sid);
if (!flag) {
System.out.println("id不存在,请重新输入!");
}
break;
case "3":
System.out.println("请输入你要修改学生的id:");
Integer sid1 = scanner.nextInt();
boolean flag1 = updateStu(students, sid1, scanner);
if (!flag1) {
System.out.println("id不存在,请重新输入!");
}
break;
case "4":
System.out.println("请输入你要查询学生的id:");
Integer sid2 = scanner.nextInt();
boolean flag2 = selectStu(students, sid2);
if (!flag2) {
System.out.println("当前无学生信息,请添加后再次查询!");
}
break;
case "5":
if (students.size() != 0) {
selectStuAll(students);
} else {
System.out.println("当前学生信息为空,请进行添加!");
}
break;
case "6":
System.exit(0);
break;
}
}
}
public static boolean delectStu(ArrayList<Student> students, Integer sid) {
for (int i = 0; i < students.size(); i++) {
Student student = students.get(i);
if (student.getId().equals(sid)) {
students.remove(i);
System.out.println("删除成功!");
return true;
}
}
return false;
}
public static boolean updateStu(ArrayList<Student> students, Integer sid, Scanner scanner) {
for (int i = 0; i < students.size(); i++) {
Student student = students.get(i);
if (student.getId().equals(sid)) {
System.out.println("请输入你要修改学生的name:");
String name1 = scanner.next();
System.out.println("请输入你要修改学生的age:");
int age1 = scanner.nextInt();
System.out.println("请输入你要修改学生的address:");
String address1 = scanner.next();
student.setName(name1);
student.setAge(age1);
student.setAddress(address1);
students.set(i, student);
System.out.println("修改成功!");
return true;
}
}
return false;
}
public static boolean selectStu(ArrayList<Student> students, Integer sid) {
for (int i = 0; i < students.size(); i++) {
Student student = students.get(i);
if (student.getId().equals(sid)) {
System.out.println("id=" + student.getId() + " name=" + student.getName() + " age=" + student.getAge() + " address=" + student.getAddress());
return true;
}
}
return false;
}
public static void selectStuAll(ArrayList<Student> students) {
for (int i = 0; i < students.size(); i++) {
Student student = students.get(i);
System.out.println("id=" + student.getId() + " name=" + student.getName() + " age=" + student.getAge() + " address=" + student.getAddress());
}
}
}
总结:
在面对如下代码:switch中嵌套for循环,显然一个break是跳不出去switch的,这样就出现了一个问题,程序运行时,当id重复后break只会跳出for循环,这样程序还会继续往下走,显然逻辑这样做的逻辑是不正确的。那么要怎么来解决呢?这里是我想出来的办法:
第一个办法:在for循环外设置一个mark标记,当id重复后来改变mark的值,从而来确定循环后的代码要不要执行
第二个办法:写一个方法,在case中直接调用方法,这样也能解决该问题。(具体实现如我上述代码的修、查、删功能)
第三个办法:为switch起一个名字loop,当id相同时直接break loop,也能直接跳出switch。(具体实现如我上述代码的增加功能)?
case "1": ? System.out.println("请输入学生的id:"); Integer id = scanner.nextInt(); for (int i = 0; i < students.size(); i++) { Student student = students.get(i); if (student.getId().equals(id)) { System.out.println("id重复,请重新输入!"); break; } } System.out.println("请输入学生的name:"); String name = scanner.next(); System.out.println("请输入学生的age:"); int age = scanner.nextInt(); System.out.println("请输入学生的address:"); String address = scanner.next(); Student stu = new Student(id, name, age, address); students.add(stu); System.out.println("添加学生成功!"); ? break;? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ??
文章来源:https://blog.csdn.net/m0_65368672/article/details/135136651
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