LeetCode(59)反转链表 II【链表】【中等】

2023-12-14 20:31:56

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链接: 反转链表 II

1.题目

给你单链表的头指针 head 和两个整数 leftright ,其中 left <= right 。请你反转从位置 left 到位置 right 的链表节点,返回 反转后的链表

示例 1:

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输入:head = [1,2,3,4,5], left = 2, right = 4
输出:[1,4,3,2,5]

示例 2:

输入:head = [5], left = 1, right = 1
输出:[5]

提示:

  • 链表中节点数目为 n
  • 1 <= n <= 500
  • -500 <= Node.val <= 500
  • 1 <= left <= right <= n

进阶: 你可以使用一趟扫描完成反转吗?


2.答案

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public static ListNode reverseBetween(ListNode head, int left, int right) {
        if (left == right) {
            return head;
        }
        ListNode node = head;
        int index = 1;
        ListNode beforeLeftNode = null;
        ListNode leftNode = null;
        ListNode rightNode = null;
        ListNode afterRightNode = null;
        ListNode beforeNode = null;
        while (node != null) {
            if (index == left) {
                beforeLeftNode = beforeNode;
                leftNode = node;
                beforeNode = node;
                node = node.next;
            } else if (index > left && index < right) {
                ListNode afterNode = node.next;
                node.next = beforeNode;
                beforeNode = node;
                node = afterNode;
            } else if (index == right) {
                afterRightNode = node.next;
                rightNode = node;
                rightNode.next = beforeNode;
                break;
            } else {
                beforeNode = node;
                node = node.next;
            }
            index++;
        }
        if (beforeLeftNode != null) {
            beforeLeftNode.next = rightNode;
        } else {
            head = rightNode;
        }
        assert leftNode != null;
        leftNode.next = afterRightNode;
        return head;
    }
}

3.提交结果截图

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整理完毕,完结撒花~ 🌻

文章来源:https://blog.csdn.net/qq_33204709/article/details/135003289
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