一年中的第几天

一年中的第几天

提示

给你一个字符串?date?，按?YYYY-MM-DD?格式表示一个?现行公元纪年法?日期。返回该日期是当年的第几天。

第一版：?

int dayOfYear(char* date) {
    int i=0;
    int year=0,month=0,day=0;
    while(date[i]!='-'){
        year*=10;
        year+=date[i]-'0';
        i++;
    }
    i++;
    year=(year%4==0&&year%100!=0)||year%400==0?1:0;
    while(date[i]!='-'){
        month*=10;
        month+=date[i]-'0';
        i++;
    }
    i++;
    while(date[i]!='\0'){
        day*=10;
        day+=date[i]-'0';
        i++;
    }
    if(month<3){
        switch(month){
            case 1:
            day=day;
            break;
            case 2:
            day+=31;
            break;
        }
    }else{
        switch(month){
            case 12:
            day+=30;
            case 11:
            day+=31;
            case 10:
            day+=30;
            case 9:
            day+=31;
            case 8:
            day+=31;
            case 7:
            day+=30;
            case 6:
            day+=31;
            case 5:
            day+=30;
            case 4:
            day+=31;
            case 3:
            day+=28+31;
            break;
        }
        if(year){
            day+=1;
        }
    }
    return day;
}

?

?第二版；

int dayOfYear(char * date){
    int year = atoi(date);
    int month = atoi(date + 5);
    int day = atoi(date + 8);
    int amount[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) {
        ++amount[1];
    }
    int ans = 0;
    for (int i = 0; i < month - 1; ++i) {
        ans += amount[i];
    }
    return ans + day;
}