Leetcode 1071. Greatest Common Divisor of Strings
2024-01-07 21:42:44
Problem
For two strings s and t, we say “t divides s” if and only if s = t + … + t (i.e., t is concatenated with itself one or more times).
Given two strings str1 and str2, return the largest string x such that x divides both str1 and str2.
Algorithm
Enumerate substrings with decreasing length.
Code
class Solution:
def gcdOfStrings(self, str1: str, str2: str) -> str:
Len1 = len(str1)
Len2 = len(str2)
for i in range(1, Len2+1):
Len = Len2 // i
if Len < 1:
return ""
if Len2 // Len * Len == Len2 and Len1 // Len * Len == Len1:
buffer = str2[0:Len]
flag1, flag2 = 1, 1
for j in range(1, Len1+1):
if j * Len > Len1:
break;
elif buffer != str1[(j-1)*Len:j*Len]:
flag1 = 0
break
for j in range(1, Len2+1):
if j * Len > Len2:
break;
elif buffer != str2[(j-1)*Len:j*Len]:
flag2 = 0
break
if flag1 and flag2:
return buffer
return ""
文章来源:https://blog.csdn.net/mobius_strip/article/details/135371356
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