力扣题:数字与字符串间转换-12.19

力扣题-12.19

[力扣刷题攻略] Re：从零开始的力扣刷题生活

力扣题1：443. 压缩字符串

解题思想：通过双指针进行遍历即可

class Solution(object):
    def compress(self, chars):
        """
        :type chars: List[str]
        :rtype: int
        """
        if len(chars) <= 1:
            return len(chars)

        write, read = 0, 0

        while read < len(chars):
            current_char = chars[read]
            count = 0

            while read < len(chars) and chars[read] == current_char:
                read += 1
                count += 1

            chars[write] = current_char
            write += 1

            if count > 1:
                for c in str(count):
                    chars[write] = c
                    write += 1

        return write

        if (chars.size() <= 1) {
            return chars.size();
        }

        int write = 0, read = 0;

        while (read < chars.size()) {
            char current_char = chars[read];
            int count = 0;

            while (read < chars.size() && chars[read] == current_char) {
                read++;
                count++;
            }

            chars[write] = current_char;
            write++;

            if (count > 1) {
                std::string count_str = std::to_string(count);
                for (char c : count_str) {
                    chars[write] = c;
                    write++;
                }
            }
        }

        return write;