Leetcode 350. Intersection of Two Arrays II
2023-12-13 08:46:30
Problem
Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must appear as many times as it shows in both arrays and you may return the result in any order.
Algorithm
Collect all the elements in each list in two conut list and then return the min size items appear in both conut list.
Code
class Solution:
def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:
item1 = [0] * 1001
item2 = [0] * 1001
for i in nums1:
item1[i] += 1
for i in nums2:
item2[i] += 1
ans = []
for i in range(1001):
if item1[i] and item2[i]:
ans += [i] * min(item1[i], item2[i])
return ans
文章来源:https://blog.csdn.net/mobius_strip/article/details/134860097
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