基于mt19937_64的字符串哈希(板子整理)

2023-12-25 00:11:51

引自tourist的哈希板子,引入和时间相关的随机值mt19937_64,所以不会被卡掉

入参:传入string

使用:

#include<bits/stdc++.h>
using namespace std;
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
typedef long long ll;
typedef double db;
typedef pair<ll,int> P;
#define fi first
#define se second
#define pb push_back
#define dbg(x) cerr<<(#x)<<":"<<x<<" ";
#define dbg2(x) cerr<<(#x)<<":"<<x<<endl;
#define SZ(a) (int)(a.size())
#define sci(a) scanf("%d",&(a))
#define scll(a) scanf("%lld",&(a))
#define pt(a) printf("%d",a);
#define pte(a) printf("%d\n",a)
#define ptlle(a) printf("%lld\n",a)
#define debug(...) fprintf(stderr, __VA_ARGS__)

mt19937_64 rng((unsigned int) chrono::steady_clock::now().time_since_epoch().count());

struct hash61 {
  static const uint64_t md = (1LL << 61) - 1;
  static uint64_t step;
  static vector<uint64_t> pw;
 
  uint64_t addmod(uint64_t a, uint64_t b) const {
    a += b;
    if (a >= md) a -= md;
    return a;
  }
 
  uint64_t submod(uint64_t a, uint64_t b) const {
    a += md - b;
    if (a >= md) a -= md;
    return a;
  }
 
  uint64_t mulmod(uint64_t a, uint64_t b) const {
    uint64_t l1 = (uint32_t) a, h1 = a >> 32, l2 = (uint32_t) b, h2 = b >> 32;
    uint64_t l = l1 * l2, m = l1 * h2 + l2 * h1, h = h1 * h2;
    uint64_t ret = (l & md) + (l >> 61) + (h << 3) + (m >> 29) + (m << 35 >> 3) + 1;
    ret = (ret & md) + (ret >> 61);
    ret = (ret & md) + (ret >> 61);
    return ret - 1;
  }
 
  void ensure_pw(int sz) {
    int cur = (int) pw.size();
    if (cur < sz) {
      pw.resize(sz);
      for (int i = cur; i < sz; i++) {
        pw[i] = mulmod(pw[i - 1], step);
      }
    }
  }
 
  vector<uint64_t> pref;
  int n;
 
  template<typename T>
  hash61(const T& s) {
    n = (int) s.size();
    ensure_pw(n + 1);
    pref.resize(n + 1);
    pref[0] = 1;
    for (int i = 0; i < n; i++) {
      pref[i + 1] = addmod(mulmod(pref[i], step), s[i]);
    }
  }
 
  inline uint64_t operator()(const int from, const int to) const {
    assert(0 <= from && from <= to && to <= n - 1);
    return submod(pref[to + 1], mulmod(pref[from], pw[to - from + 1]));
  }
};
 
uint64_t hash61::step = (md >> 2) + rng() % (md >> 1);
vector<uint64_t> hash61::pw = vector<uint64_t>(1, 1);

string s;
int n;
int main(){
	ios::sync_with_stdio(0);
	cin.tie(0);cout.tie(0);
	cin>>n>>s;
	auto hs=hash61(s);
	int l=0,r=n-1;
	cout<<hs(l,r)<<endl;
	return 0;
}

文章来源:https://blog.csdn.net/Code92007/article/details/135188295
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