基本链表操作

2024-01-07 21:21:25

答案

#include<stdio.h>
#include<malloc.h>
#define LEN sizeof(struct list)
struct list {
int num;
struct list *next;
};
int n;
struct list *create(void) {
struct list *head;
struct list *p1,*p2;
n=0;
p1=p2=(struct list *)malloc(LEN);
scanf("%d",&p1->num);
head=NULL;
while (p1->num!=-1) {
n++;
if (n == 1)
head=p1;
else
p2->next=p1;
p2=p1;
p1=(struct list *)malloc(LEN);
scanf("%d",&p1->num);
}
p2->next=NULL;
return head;
}
struct list *delnode(struct list *h,int x) {
struct list *head,*p,*q;
head=(struct list *)malloc(LEN);
head->next=h;
p=head->next;
q=head;
while (p!=NULL) {
if (p->num == x) {
q->next=p->next;
free(p);
p=q->next;
}
else {
q=p;
p=p->next;
}
}
q=head;
head=head->next;
free(q);
return head;
}
void print(struct list *head) {
int tmp[20];
int i,j;
struct list *p;
p=head;
if (head != NULL)
{
/*do
{
printf("%d ",p->num);
p=p->next;
}while (p!=NULL);*/
i = 0;
while (p != NULL)
{
tmp[i++] = p->num;
p = p->next;
}
for (j=i-1;j>=0;j--)
printf("%d ",tmp[j]);
}
}
int main() {
struct list *head;
int x;
head=create();
scanf("%d",&x);
head=delnode(head,x);
print(head);
return 0;
}

文章来源:https://blog.csdn.net/CTJ_c/article/details/135434133
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