SCAU:18064 链表的有序合并

2023-12-21 07:00:16

18064?链表的有序合并

时间限制:1000MS? 代码长度限制:10KB
提交次数:0 通过次数:0

题型: 填空题???语言: G++;GCC;VC

Description

已知有两个链表a和b,结点类型相同,均包括一个int类型的数据。编程把两个链表合并成一个,结点按升序排列。


#include?"stdio.h"
#include?"malloc.h"
#define?LEN?sizeof(struct?DATA)

struct?DATA
{
?????long?num;
?????struct?DATA?*next;
};

struct?DATA?*create(int?n)
{
?????struct?DATA?*head=NULL,*p1=NULL,*p2=NULL;
?????int?i;
?????for(i=1;i<=n;i++)
?????{??p1=(struct?DATA?*)malloc(LEN);
????????scanf("%ld",&p1->num);
????????p1->next=NULL;
????????if(i==1)?head=p1;
????????else?p2->next=p1;
????????p2=p1;
??????}
??????return(head);
}

struct?DATA?*merge(struct?DATA?*head,?struct?DATA?*head2)
{
????_______________________
????return?head;
}

struct?DATA?*insert(struct?DATA?*head,?struct?DATA?*d)
{
????_______________________
????return?head;
}

struct?DATA?*sort(struct?DATA?*head)?
{?
????_______________________
????return?head;
}?

void?print(struct?DATA?*head)
{
????struct?DATA?*p;
????p=head;
????while(p!=NULL)
????{
????????printf("%ld",p->num);
????????p=p->next;
????????printf("\n");
????}
}

main()
{
????struct?DATA?*head,?*head2;
????int?n;
????long?del_num;
????scanf("%d",&n);
????head=create(n);
????scanf("%d",&n);
????head2=create(n);
????head?=?merge(head,?head2);
????head?=?sort(head);
????print(head);
}
?

输入格式

第一行一个数n,表示第一个列表的数据个数
每二行为n个数
第三行为一个数m
第四行为m个数

输出格式

输出合并后的有序的数据,一行一个数

输入样例

2
4 8
3
9 1 5

输出样例

1
4
5
8
9

#include "stdio.h"
#include "malloc.h"
#define LEN sizeof(struct DATA)

struct DATA
{
     long num;
     struct DATA *next;
};

struct DATA *create(int n)
{
     struct DATA *head=NULL,*p1=NULL,*p2=NULL;
     int i;
     for(i=1;i<=n;i++)
     {  p1=(struct DATA *)malloc(LEN);
        scanf("%ld",&p1->num);
        p1->next=NULL;
        if(i==1) head=p1;
        else p2->next=p1;
        p2=p1;
      }
      return(head);
}

struct DATA *merge(struct DATA *head, struct DATA *head2)
{
    struct DATA *p1;
    p1=head;
    while(p1->next!=NULL)
    {
        p1=p1->next;
    }
    p1->next=head2;
    return head;
}

struct DATA *insert(struct DATA *head, struct DATA *d)
{
    struct DATA *p1,*p2,*p3;
    p1=head;
    p2=d;
    if(head==NULL)
    {
        head=p2;
        p2->next=NULL;
    }
    else
    {
        while((p1->num < p2->num) && (p1->next!=NULL))
        {
            p3=p1;
            p1=p1->next;
        }
        if(p1->num >= p2->num)
        {
            if(head==p1)
                head=p2;
            else
                p3->next=p2;
            p2->next=p1;
        }
        else
        {
            p1->next=p2;
            p2->next=NULL;
        }
    }
    return head;
}

struct DATA *sort(struct DATA *head) 
{ 
    struct DATA *p1,*p2;
    p2=head;
    p1=head;
    p2=p2->next;
    p1->next=NULL;
    p1=p2;
    while(p2->next!=NULL)
    {
        p2=p2->next;
        p1->next=NULL;
        head=insert(head,p1);
        p1=p2;
    }
    head=insert(head,p1);
    return head;
} 

void print(struct DATA *head)
{
    struct DATA *p;
    p=head;
    while(p!=NULL)
    {
        printf("%ld",p->num);
        p=p->next;
        printf("\n");
    }
}

main()
{
    struct DATA *head, *head2;
    int n;
    long del_num;
    scanf("%d",&n);
    head=create(n);
    scanf("%d",&n);
    head2=create(n);
    head = merge(head, head2);
    head = sort(head);
    print(head);
}

?

文章来源:https://blog.csdn.net/zero_019/article/details/135120394
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