数据库(三)超详细SQL语句入门 | SQL增删改查,重命名,字符操作,联合操作,聚合函数,嵌套子查询
文章目录
1 SQL表内类型
char(n) 固定长度n的字符
varchar(n) 最大长度n的字符
int 整形
smallint 小整形
numeric(p,d ) 固定小数点位数,特定精度 如 numeric(3,1) 支持 44.5
float
double
2 SQL增删改语句
2.1 创建表
语法
注意不要丢掉分号
示例:
create table department(
dept_name varchar(20),
building varchar(15),
budget numeric (12,2),
primary key(dept_name)
);
指定主键
primary key(dept_name)
指定非空属性
dept_name varchar(20) not null
制定外键
foreign key (name) references instructor
2.2 删除表
drop table r;
2.3 表中添加属性
alter table r add A D;
为表添加A D属性
2.4 添加新的元组信息
insert into instructors values("10211","Simith","Biology")
2.5 删除表所有元组
delete from instructor
2.6 元组
示例:给收入低于 70000 的教师加薪 5%
update instructor
set salary = salary * 1.05
where salary < 70000;
3 查询语句
查询结构
select 属性
from 表
where 谓词条件
多个表的时候,需要加表名.属性区分
select name, instructor.dept_name, building
from instructor, department
where instructor.dept_name= department.dept_name;
注意
1 SQL语句大小写不敏感 name=NAME
2 选择结果可能会包含重复的结果
使用distinct去除重复
select distinct dept_name
from instructor;
3 使用*查询全部
select * from instructor;
4 选择中可以包括运算表达式
select ID, name, salary/12 as monthly_salary
from instructor;
表示选择工资除以12后选择出来
5 where谓词
select name
from instructor
where dept_name = 'Comp. Sci.' and salary > 70000;
select name, instructor.dept_name, building
from instructor, department
where instructor.dept_name = department.dept_name;
4 重命名
4.1 为什么用
as
1 在相同的关系中比较元组
示例:查找 Comp.Sci 部门中薪水高于至少一名讲师的所有讲师的姓名。
select distinct T.name
from instructor as T, instructor as S
where T.salary > S.salary and S.dept_name = 'Comp. Sci';
2 将长的名字改短
select T.name, S.course_id
from instructor as T, teaches as S
where T.ID= S.ID;
3 结果属性修改名称
select T.name as instructor_name, S.course_id
from instructor as T, teaches as S
where T.ID= S.ID;
5 字符操作
5.1 寻找
like
% 子字符串匹配
__ 匹配任何字符串
举例
'Intro%' matches any string beginning with “Intro”.
'%Comp%' matches any string containing “Comp” as a substring.
'_ _ _' matches any string of exactly three characters.
'_ _ _ %' matches any string of at least three characters.
注意
1 大小写敏感
2 转义字符区分%
Match the string “100%”
like ‘100 %’
6 生序降序
order关键字
desc 降序
asc升序
示例1:按字母顺序列出物理系的所有教师
select name
from instructor
where dept_name = 'Physics'
order by name;
示例2:按薪水和姓名列出讲师
select *
from instructor
order by salary desc, name asc;
between
select name
from instructor
where salary between 90000 and 100000
等价于
select name
from instructor
where salary <= 100000 and salary >= 90000;
7 联合操作
7.1 并集Union
可以直接自动消除重复,不像选择子句。
例子1 :查找 2017 年秋季或 2018 年春季开设的课程
select course_id
from section
where semester = 'Fall' and year = 2017
union
select course_id
from section
where semester = 'Spring' and year = 2018;
如果我们想要保留所有重复值
用union all
select course_id
from section
where semester = 'Fall' and year = 2017
union all
select course_id
from section
where semester = 'Spring' and year = 2018;
7.2 交集 INTERSECT
select course_id
from section
where semester = 'Fall' and year = 2017
intersect
select course_id
from section
where semester = 'Spring' and year = 2018;
7.3 差集 EXCEPT
select course_id
from section
where semester = 'Fall' and year = 2017
except
select course_id
from section
where semester = 'Spring' and year = 2018;
7.4 对于空值补充
1 任何包含Null的表达式返回为Null
例:
5 + null returns null
2 任何包含Null的比较返回的值是未知的
例
5 < null or null <> null or null = null returns unknown
3 对于布尔运算
and : (true and unknown) = unknown,
(false and unknown) = false,
(unknown and unknown) = unknown
or: (unknown or true) = true,
unknown or false) = unknown
(unknown or unknown) = unknown
空值,未知检测
示例:查找工资为空的所有教师。
select name
from instructor
where salary is null/ unknown
都是用is的,注意不能用=来替代is 在null的情况下
8 聚合函数
Average: avg
Minimum: min
Maximum: max
Total: sum
Count: count
示例:查找计算机科学系教师的平均工资
select avg (salary) as avg_salary
from instructor
where dept_name = 'Comp. Sci.';
8.1 group by
group by是一个限定函数,意味着在这种情况下,限定在哪里的一个范围内进行比较寻找
比如下面的例子,要找到每一个部门的平均值
示例:查找每个部门讲师的平均工资
select dept_name, avg (salary) as avg_salary
from instructor
group by dept_name;
8.2 having
示例:查找平均工资大于42000的所有部门的名称和平均工资
having相当于就是给Group加一个条件,比如在这个范围内大于42000的
select dept_name, avg (salary) as avg_salary
from instructor
group by dept_name
having avg (salary) > 42000;
9 Nested Subqueries 嵌套子查询
9.1 Set Membership
in 和not in
示例: 查找所有姓名为“莫扎特”或“爱因斯坦”的教师
select distinct name
from instructor
where name in("Mozart","Einstein")
示例:查找已参加 ID 为 10101 的教师教授的课程部分的(不同)学生总数
select count (distinct ID)
from takes
where (course_id, sec_id, semester, year) in (select course_id, sec_id, semester, year
from teaches
where teaches.ID= 10101);
9.2 Set Comparison
SQL also allows < some, <= some, >= some, = some, and <> some
定义: y < some (X) : y小于X中任一元素,则结果为true
比较
some 只要一个满足即可
all 所有满足
9.3 exist or not exists
示例: 查找学过生物系所有课程的学生(ID、姓名)。
select S.ID, S.name
from student as S
where not exists ( (select course_id
from course
where dept_name = 'Biology')
except
(select T.course_id
from takes as T
where S.ID = T.ID));
9.4 with as
临时的关系,一会儿的查询用到
示例: 查找预算最高的所有部门
with max_budget (value) as
(select max(budget)
from department)
select department.name
from department, max_budget
where department.budget = max_budget.value;
本文来自互联网用户投稿,该文观点仅代表作者本人,不代表本站立场。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。 如若内容造成侵权/违法违规/事实不符,请联系我的编程经验分享网邮箱:veading@qq.com进行投诉反馈,一经查实,立即删除!