Python用Pygame实现一个五子棋小游戏
2023-12-19 23:09:52
下面是一个使用Pygame包实现的五子棋小游戏的示例代码:
import pygame
import sys
# 初始化游戏
pygame.init()
# 设置窗口大小
WIDTH = 640
HEIGHT = 480
SIZE = 15
MARGIN = 20
BOARD_SIZE = SIZE * MARGIN + MARGIN
WINDOW_SIZE = (WIDTH, HEIGHT)
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
BLUE = (0, 0, 255)
# 创建游戏窗口
screen = pygame.display.set_mode(WINDOW_SIZE)
pygame.display.set_caption("五子棋")
# 创建棋盘
board = [[0 for _ in range(SIZE)] for _ in range(SIZE)]
# 绘制棋盘
def draw_board():
screen.fill(WHITE)
for row in range(SIZE):
for col in range(SIZE):
pygame.draw.rect(screen, BLACK, (MARGIN + col * MARGIN, MARGIN + row * MARGIN, MARGIN, MARGIN), 1)
if board[row][col] == 1:
pygame.draw.circle(screen, BLACK, (MARGIN + col * MARGIN, MARGIN + row * MARGIN), MARGIN // 2)
elif board[row][col] == 2:
pygame.draw.circle(screen, BLUE, (MARGIN + col * MARGIN, MARGIN + row * MARGIN), MARGIN // 2)
# 判断胜利条件
def check_win(row, col, player):
# 判断水平方向
count = 1
i = 1
while col + i < SIZE and board[row][col + i] == player:
count += 1
i += 1
i = 1
while col - i >= 0 and board[row][col - i] == player:
count += 1
i += 1
if count >= 5:
return True
# 判断垂直方向
count = 1
i = 1
while row + i < SIZE and board[row + i][col] == player:
count += 1
i += 1
i = 1
while row - i >= 0 and board[row - i][col] == player:
count += 1
i += 1
if count >= 5:
return True
# 判断左斜方向
count = 1
i = 1
while row + i < SIZE and col + i < SIZE and board[row + i][col + i] == player:
count += 1
i += 1
i = 1
while row - i >= 0 and col - i >= 0 and board[row - i][col - i] == player:
count += 1
i += 1
if count >= 5:
return True
# 判断右斜方向
count = 1
i = 1
while row + i < SIZE and col - i >= 0 and board[row + i][col - i] == player:
count += 1
i += 1
i = 1
while row - i >= 0 and col + i < SIZE and board[row - i][col + i] == player:
count += 1
i += 1
if count >= 5:
return True
return False
# 游戏主循环
def main():
player = 1 # 玩家1为黑子,玩家2为蓝子
running = True
game_over = False
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
sys.exit()
if not game_over and event.type == pygame.MOUSEBUTTONDOWN:
if pygame.mouse.get_pressed()[0]:
x, y = event.pos
col = (x - MARGIN) // MARGIN
row = (y - MARGIN) // MARGIN
if row >= 0 and row < SIZE and col >= 0 and col < SIZE and board[row][col] == 0:
board[row][col] = player
draw_board()
pygame.display.update()
if check_win(row, col, player):
msg = "玩家{}赢了!".format(player)
font = pygame.font.Font(None, 36)
text = font.render(msg, True, BLACK)
screen.blit(text, (WIDTH // 2 - text.get_width() // 2, HEIGHT // 2 - text.get_height() // 2))
pygame.display.update()
game_over = True
else:
player = 2 if player == 1 else 1
if not game_over:
draw_board()
pygame.display.update()
pygame.quit()
if __name__ == "__main__":
main()
这个代码创建了一个基于Pygame的五子棋游戏窗口,并通过鼠标点击来下棋。玩家1使用黑子,玩家2使用蓝子。游戏结束时会显示胜利信息。你可以根据需要对代码进行修改和优化。请确保已安装Pygame包,并将上述代码保存为.py
文件运行即可开始游戏。
文章来源:https://blog.csdn.net/xukris/article/details/135089218
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