寒假刷题记录,第三天
2024-01-10 12:01:19
PTA甲级
1009 Product of Polynomials
多项式乘法
#include<iostream>
#include<algorithm>
#include<vector>
#include<unordered_map>
using namespace std;
const int N = 1010;
int n;
unordered_map<int , double>a , res;
int main()
{
cin >> n;
for(int i = 0;i < n;i ++)
{
int idx;
double x;
cin >> idx >> x;
a[idx] = x;
}
cin >> n;
for(int i = 0;i < n;i ++)
{
int idx;
double x;
cin >> idx >> x;
for(auto j : a)
res[j.first + idx] += x * j.second;
}
vector<pair<int , double>>v;
for(auto i : res)
if(i.second) v.push_back({i.first , i.second});
sort(v.begin() , v.end());
reverse(v.begin() , v.end());
cout << v.size();
for(auto i : v)
printf(" %d %.1lf" , i.first , i.second);
return 0;
}
1012 The Best Rank
排序
#include <cstdio>
#include <algorithm>
using namespace std;
struct node {
int id, best;
int score[4], rank[4];
}stu[2005];
int exist[1000000], flag = -1;
bool cmp1(node a, node b) {return a.score[flag] > b.score[flag];}
int main()
{
int n, m, id;
scanf("%d %d", &n, &m);
for(int i = 0; i < n; i++)
{
scanf("%d %d %d %d", &stu[i].id, &stu[i].score[1], &stu[i].score[2], &stu[i].score[3]);
stu[i].score[0] = (stu[i].score[1] + stu[i].score[2] + stu[i].score[3]) / 3.0 + 0.5;
}
for(flag = 0; flag <= 3; flag ++)
{
sort(stu, stu + n, cmp1);
stu[0].rank[flag] = 1;
for(int i = 1; i < n; i ++)
{
stu[i].rank[flag] = i + 1;
if(stu[i].score[flag] == stu[i-1].score[flag])
stu[i].rank[flag] = stu[i-1].rank[flag];
}
}
for(int i = 0; i < n; i++)
{
exist[stu[i].id] = i + 1;
stu[i].best = 0;
int minn = stu[i].rank[0];
for(int j = 1; j <= 3; j ++)
{
if(stu[i].rank[j] < minn)
{
minn = stu[i].rank[j];
stu[i].best = j;
}
}
}
char c[5] = {'A', 'C', 'M', 'E'};
for(int i = 0; i < m; i++)
{
scanf("%d", &id);
int temp = exist[id];
if(temp)
{
int best = stu[temp - 1].best;
printf("%d %c\n", stu[temp - 1].rank[best], c[best]);
}
else printf("N/A\n");
}
return 0;
}
1013 Battle Over Cities
经典并查集
#include<iostream>
using namespace std;
const int N = 10100 , M = 1e6 + 10;
int n , m , k;
int p[N];
struct node
{
int a , b;
}nodes[M];
int find(int x)
{
if(p[x] != x) p[x] = find(p[x]);
return p[x];
}
int main()
{
scanf("%d %d %d" , &n , &m , &k);
for(int i = 0;i < m;i ++) scanf("%d %d" ,&nodes[i].a ,&nodes[i].b);
while(k --)
{
int x;
scanf("%d" ,&x);
int res = n - 1;
for(int i = 1;i <= n;i ++) p[i] = i;
for(int i = 0;i < m;i ++)
{
int a = nodes[i].a , b = nodes[i].b;
if(a != x && b != x)
{
int pa = find(a) , pb = find(b);
if(pa != pb) p[pa] = pb , res --;
}
}
printf("%d\n" , res - 1);
}
return 0;
}
文章来源:https://blog.csdn.net/xp_xht123/article/details/135494974
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